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Git repo for my side projects and apps - digitalnalogika
======
digitalnalogika
I will constantly update this repo with my side projects and apps. Hopefully
it will motivate some people to create similar projects of their own.
~~~
CamouflagedKiwi
This is a really well put together repo.
------
elfconseco
I'm wondering if the stream of links make sense. It seems like a nice idea, but
I'll be more likely to visit your personal site and read and evaluate the
projects you put in here (or just watch it tick), instead of the fact that I
have to click on a link to see them.
Maybe a better approach to putting this into use for someone would be to link
to a gitbook + knitr page or something?
~~~
vhf
Do you want to know the complete source code of the side projects, or just
want to see them?
Like StackOverflow, StackExchange or some of the Git-for-Free clones, a link
to a personal website is fine if it is equivalent (unless it's a mega-project
or a derivative).
~~~
elfconseco
I want to know the source code of the side projects, and in addition I want to
see them.
The problem with your github repo is that the project pages take you to the
streaming of links (which in theory should work, but my experience is that it
just feels confusing).
~~~
mrcactu5
[ \- I'll try to
write something similar
------
foofunk
Just put them on your Github profile page...
~~~
digitalnalogika
I know but that would mean that I would have to add my main github repo
(business app) to that. I might do
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Wyszkowo () is a village in the administrative district of Gmina Janowice Wielkie, within Jelenia Góra County, Lower Silesian Voivodeship, in south-western Poland. Prior to 1945 it was in Germany.
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References
WyszkowoQ:
How to show that $2\cos(x)=3\sin(x)$ has more than one solution
How can we show that $$2\cos(x)=3\sin(x)$$ has more than one solution?
A:
Two cosine functions cancel out. We have $3-2\cos(x)=3\sin(x)$ which is zero for $\sin(x)=0$, hence for any real number.
Q:
Numpy: Comparing 2 element arrays with numpy.where()
I have 2 arrays with shape (m,), and I want to get an array with shape (m, n), where the elements of array A are compared with those of B and they are both equal. In an ideal world, they are equal if A[i,j] == B[i,j], where i==1,2,...,m and j==1,2,...,n.
How do I do that in a smart way?
I have tried numpy.where() and got only the results I want for the case of an m x n matrix of 1s and 0s. A and B are not of that type and for a matrix of that type, the result of numpy.where() is not the result I want.
A:
Try numpy.log